Somenath Sinha February 2016
Why does integer division truncation not occur here?
I was going through the examples in K&R, and stumbled upon this bit of code:
celcius=5 * (fahr-32) / 9;
The author says that we can't use 5/9 since integer division truncation will lead to a value of 0.
The program however, outputs 17 as answer when fahr=0. By my calculations, (0-32)/9 should lead to -3 (due to truncation) and then -3*5 = -15, and NOT -17. Why does this happen?
gnasher729 February 2016
(0 - 32) is first multiplied by 5, giving -160. -160 / 9 = -17.
Asked in February 2016
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