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David M February 2016
### Numpy Deep Copy Array

I'm having some trouble copying an array using numpy. I'm running a few different sort functions and comparing run times, so I need a copy of the original array and one I modify. Here's the code I've got.

```
import numpy
import random
SIZE = 10
DISPLAY = True
def random_fill():
return numpy.array([random.random()*10000 for i in range(SIZE)])
def copy(p):
return numpy.copy(p)
def display(p):
if (DISPLAY):
print a
print
def bubble_sort(array):
temp = 0
for i in range(SIZE, 1, -1):
for j in range(1, i):
if (array[j-1] > array[j]):
temp = array[j-1]
array[j-1] = array[j]
array[j] = temp
a = random_fill()
b = copy(a)
display(a)
display(b)
bubble_sort(a)
display(a)
display(b)
```

First `a`

and `b`

display properly, being a random array. Then `a`

sorts and displays correctly but `b`

displays exactly what `a`

is. `b`

should remain unsorted. What's the issue here?

You shouldn't use `print a`

but `print p`

otherwise you print the global array instead of the one passed to the function.

Asked in February 2016

Viewed 1,012 times

Voted 11

Answered 1 times

Viewed 1,012 times

Voted 11

Answered 1 times